[LeetCode]Longest Continuous Increasing Subsequence 最长连续增长序列

链接https://leetcode.com/problems/longest-continuous-increasing-subsequence/description/

难度:Easy

题目:674. Longest Continuous Increasing Subsequence

Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).

Example 1:

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Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3.
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.

Example 2:

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Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1.

Note:

  • Length of the array will not exceed 10,000.

翻译:给定一个无序整型数组,找出最长的连续增长的子序列。

思路:设置一个标志符flag,遍历整个数组,如果后一个值比前一个值大,则res取res和flag中的最大值,否则flag置1。

参考代码

Java

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class Solution {
public int findLengthOfLCIS(int[] nums) {
if(nums.length <=1)
return nums.length;
int res = 0;
int flag = 0;
for(int i=0; i<nums.length; i++)
if(i==0 || nums[i]>nums[i-1])
res = Math.max(res, ++flag);
else
flag = 1;
return res;
}
}